1. Tardigrade
  2. Question
  3. Chemistry
  4. For the equilibrium N 2 O 4( g ) leftharpoons 2 NO 2( g ), the equilibrium constant KP=0.112 at 298 K. If the partial pressure of NO 2 in the equilibrium mixture is 0.40 atm the partial pressure of N 2 O 4 would be

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Q. For the equilibrium $N _{2} O _{4}( g ) \rightleftharpoons 2 NO _{2}( g ),$ the equilibrium constant $K_{P}=0.112$ at $298\, K$. If the partial pressure of $NO _{2}$ in the equilibrium mixture is $0.40\, atm$ the partial pressure of $N _{2} O _{4}$ would be

Equilibrium

Solution:

$K_{p}= \frac{ p _{ NO _{2}}^{2}}{ p _{ N _{2} O _{4}}}$
$ p N _{2} O _{4}=\frac{p_{ NO 2}^{2}}{K_{p}}=\frac{(0.4)^{2}}{0.112}=1.43\, atm$