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Chemistry
For the equation log k = 5 â (2000/T) The incorrect statement is
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Q. For the equation log k = 5 − $\frac{2000}{T}$ The incorrect statement is
A
The rate constant will increase with increase of temperature
B
The graph of log $k$ vs $\frac {1}{T}$ will have a negative slope
C
The value of activation energy is - $2000/T$ for the reaction
D
Both (1) and (3)
Solution:
Correct answer is (c) The value of activation energy is - $2000/T$ for the reaction