Question

For the electrode reaction, $ {{M}^{n+}}(aq)+n{{e}^{-}}\xrightarrow[{}]{{}}M(s) $ Nernst equation is

• A. $ E=E{}^\circ +\frac{RT}{nF}\log \frac{1}{[{{M}^{n+}}]} $
• B. $ E{}^\circ =E+RT\,in\,[{{M}^{n+}}] $
• C. $ E=E{}^\circ -\frac{RT}{nF}\,in\frac{1}{\,[{{M}^{n+}}]} $
• D. $ \frac{E}{E{}^\circ }=\frac{RT}{nF}\,in[{{M}^{n+}}] $

Answer 1

Answer: (C)

For the electron reaction, $ {{M}^{n+}}(aq)+n{{e}^{-}}\xrightarrow[{}]{{}}M(s) $ Nernst equation is $ E=E{}^\circ -\frac{RT}{nF}in\frac{1}{[{{M}^{n+}}]} $