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  4. For the dissociation reaction, H 2( g ) arrow 2 H ( g ) Δ H =162 Kcal, heat of atomisation of H is

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Q. For the dissociation reaction, $H _{2}( g ) \rightarrow 2 H ( g ) \quad \Delta H =162 Kcal$, heat of atomisation of $H$ is

BITSATBITSAT 2013

Solution:

$\Delta H =\Delta H _{(\text {product })}-\Delta H _{(\text {reactant })}$
$162=2 \times \Delta H _{ H }-\Delta H _{ H _{2}}$
$\Delta H _{ H }=\frac{162}{2}\left(\because \Delta H _{ H _{2}}=0\right)$
$\Delta H _{ H }=81\, Kcal$