Question

For the combustion reaction at $298\, K$
$H _{2}( g )+\frac{1}{2} O _{2}( g ) \rightarrow H _{2} O (\ell)$
Which of the following alternative (s) is/are correct?

• A. $\Delta H =\Delta E$
• B. $\Delta H >\Delta E$
• C. $\Delta H <\Delta E$
• D. $\Delta H$ and $\Delta E$ has no relation with each other

Answer 1

Answer: (C)

$\Delta n = - \frac{1}{2} - 1 = -\frac{3}{2}$
Since, $\Delta n < 0$
$\therefore \Delta H < \Delta E$