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  4. For the circuit shown, with R1 = 1.0 Ω , R2 = 2.0 Ω , E1 = 2 V and E2 = E3 = 4 V, the potential difference between the points 'a' and 'b' is approximately (in V) :

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Q. For the circuit shown, with $R_1 = 1.0 \Omega , R_2 = 2.0 \Omega , E_1 = 2 V$ and $E_2 = E_3 = 4 V$, the potential difference between the points $'a'$ and $'b'$ is approximately (in $V$) :Physics Question Image

JEE MainJEE Main 2019Current Electricity

Solution:

$E_{eq} = \frac{\frac{E_{1}}{2R_{1}} + \frac{E_{2}}{R_{2}} + \frac{E_{3}}{2R_{1}}}{\frac{1}{2R_{1}} + \frac{1}{R_{2}} + \frac{1}{2R_{1}}} $
$ = \frac{\frac{2}{2} + \frac{4}{2} + \frac{4}{2}}{\frac{1}{2} + \frac{1}{2} + \frac{1}{2} } $
$ = \frac{5}{\frac{3}{2}} = \frac{10}{3} = 3.3 $