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  4. For the circuit shown in the figure: <img class=img-fluid question-image alt=Question src=https://cdn.tardigrade.in/q/nta/p-ko7udsoaxufa.png />

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Q. For the circuit shown in the figure :

Question

NTA AbhyasNTA Abhyas 2020Semiconductor Electronics: Materials Devices and Simple Circuits

Solution:

Here, $I=\frac{7 0}{5 0 0 0}=\text{1.4}\times 10^{- 2}A$
$V_{\text{Z}}=120-70$
$=50V$ (output voltage Across diode)
$I_{L}=\frac{5 0}{1 0 0 0 0}=5\times 10^{- 3}A=\text{0.5}\times 10^{- 2}A$
$\Rightarrow I_{\text{Z}}=\left(\text{1.4} - \text{0.5}\right)\times 10^{- 2}A$
$=9\times 10^{- 3}A$
$=9mA$