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  4. For the circuit shown in figure, the impedance of the circuit will be

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Q. For the circuit shown in figure, the impedance of the circuit will bePhysics Question Image

Jharkhand CECEJharkhand CECE 2012

Solution:

Current through inductance, $ {{i}_{L}}=\frac{90}{30}=3A $
Current through capacitor, $ {{i}_{C}}=\frac{90}{20}=4.5A $
Net current through circuit $ i={{i}_{C}}-{{i}_{L}}=4.5-3=1.5A $
$ \therefore $ Impedance of the circuit,
$ Z=\frac{V}{i}=\frac{90}{1.5}=60\Omega $