Question

For the circuit shown in figure the charge on $4\mu F$ capacitor is

• A. 40 $\mu $ C
• B. 30 $\mu $ C
• C. 24 $\mu $ C
• D. 54 $\mu $ C

Answer 1

Answer: (C)

Combined capacity of $1 \, \mu F$ and $5\mu F \, $
$=1+5=$ $6 \, \mu F$
Now, $4\mu F \, $ and $6\mu F$ are in series.
$\therefore \, \, \frac{1}{C_{s}}=\frac{1}{4}+\frac{1}{6}=\frac{3 + 2}{12}=\frac{5}{12}$
$C_{s}=\frac{12}{5}\mu F$
Charge in the arm containing $ \, 4\mu F \, $ capacitor is
$q=C_{s}\times V=\frac{12}{5}\times 10=24 \, \mu C$