1. Tardigrade
  2. Question
  3. Chemistry
  4. For the bimolecular gaseous reaction: 2R(g) arrow Product, the fraction of molecules having sufficient energy for effective collision is 2.06× 10- 9 at 127° C . The activation energy for reaction is about (ln 2 . 06 = 0 . 727 , ln 10 = 2 . 303)

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Q. For the bimolecular gaseous reaction: $2R\left(g\right) \rightarrow $ Product, the fraction of molecules having sufficient energy for effective collision is $2.06\times 10^{- 9}$ at $127^\circ C$ . The activation energy for reaction is about $\left(ln 2 . 06 = 0 . 727 , ln 10 = 2 . 303\right)$

NTA AbhyasNTA Abhyas 2022

Solution:

The fraction of effective collisions $=e^{\left(- \frac{Ea}{RT}\right)}$
$2.06\times 10^{- 9}=e^{\left(- \frac{Ea}{1 . 98 \times 400}\right)}$
$\ln \left(2.06 \times 10^{-9} \quad\right)=-\frac{ Ea }{1.98 \times 400}$
$Ea\approx16kcal/mole$