Thank you for reporting, we will resolve it shortly
Q.
For the arrangement shown in figure-$2.168$, the tension in the string to prevent it from sliding down, is :
Laws of Motion
Solution:
Maximum friction force which can act on block is,
$f_{\max } =\mu N $
$=0.8 \times(1)(10) \cos 37^{\circ} $
$=8 \times \frac{4}{5}=6.4 N$
$m g \sin \theta=10 \times \frac{3}{5}=6 N$
$\Rightarrow m g \sin \theta< f_{\max }$, the block will not slide at also no tension is required in string to hold it at rest.
