Question

For the $AC$ circuit shown in the figure the reading of ammeter and voltmeter are $5 A$ and $50 \sqrt{5} V$, respectively. The rms value of AC source (in volt) is

Answer 1

$V=i \times \sqrt{100+X_{C}^{2}}$
$50 \sqrt{5}=5 \sqrt{100+X_{C}^{2}}$
$X_{C}=20 \Omega=\frac{10^{6}}{\omega \times 50}$
$\omega=10^{3} $ rad / s
$\Rightarrow X_{L}=\omega L=20 \times 10^{-3} \times 10^{3}=20 \Omega$
$\therefore $ The circuit is in resonance.
$V=i R=50\, V$