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Q.
For same energy, find the ratio of $\lambda_{\text {photon }}$ and $\lambda_{\text {electron }}$ (Here $m$ is mass of electron)
Dual Nature of Radiation and Matter
Solution:
Energy of photon $=\frac{h c}{\lambda_{P}}$
$\lambda_{P}=\frac{h c}{E} $
$\lambda_{e}=\frac{h}{\sqrt{2 m E}} $
$\frac{\lambda_{P}}{\lambda_{\theta}}=c \sqrt{\frac{2 m}{E}}$