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Q.
For $s$-orbitals, since ($\psi$ orbital wave function) is independent of angles, the probability density ($\psi\text{2}$) is
Structure of Atom
Solution:
For spherical orbital
$\psi =f(f)$ (r = distance from nucleus)
since $\psi$ (orbital) is independent of angles therefore probability $(\psi\text{2})$ also independent of angles and spherically symmetric