Question

For redox reaction, $ F{{e}^{2+}}(aq)+C{{r}_{2}}O_{7}^{2-}(aq)+{{H}^{+}}(aq)\xrightarrow{{}} $ $ F{{e}^{3+}}(aq)+C{{r}^{3+}}(aq)+{{H}_{2}}O(l) $ The coefficients of $ F{{e}^{2+}},C{{r}_{2}}O_{7}^{2-} $ and $ {{H}^{+}} $ in the balanced reaction are

• A. $ 6,1,14 $
• B. $ 3,2,6 $
• C. $ 2,3,6 $
• D. $ 6,4,12 $

Answer 1

Answer: (A)

$ 6F{{e}^{2+}}(aq)+C{{r}_{2}}O_{7}^{2-}(aq)+14{{H}^{+}}(aq)\xrightarrow{{}} $ $ 6F{{e}^{3+}}(aq)+2C{{r}^{3+}}(aq)+7{{H}_{2}}O(l) $