1. Tardigrade
  2. Question
  3. Chemistry
  4. For reaction A(g) + B(g)leftharpoons AB(g) we start with 2 moles of A and B each. At equilibrium 0.8 moles of AB is formed. Then how much of A changes to AB

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Q. For reaction $A(g) + B(g)\rightleftharpoons AB(g)$ we start with $2$ moles of $A$ and $B$ each. At equilibrium $0.8$ moles of $AB$ is formed. Then how much of $A$ changes to $AB$

Equilibrium

Solution:

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$\therefore \%$ of A changed to A B $=\frac{0.8}{2} \times 100=40\%$