Question

For nth order reaction,
$\left(\frac{d x}{d t}\right)=$ rate $= k [ A ]^{ n }$
Graphs between log (rate) and log $\left[ A _{0}\right]$ are of the type $\left(\left[ A _{0}\right]\right.$ is the initial concentration)

Lines $P, Q, R$ and $S$ are for the order

• A. P-0, Q-1, R-2, S-3
• B. P-0, Q-3, R-2, S-1
• C. P-1, Q-2, R-3, S-0
• D. P-3, Q-2, R-1, S-0

Answer 1

Answer: (D)

$\log \left(\frac{d x}{d t}\right)=\log\, k+n / y[A]$

$n =$ order of the reaction $=$ slope of the line

Larger the value of the slope of the line, larger the order.

Thus, $P =3, Q =2, R =1, S =0$