Question

For $NH_{4}HS\left(\right.s\left.\right)\rightleftharpoonsNH_{3}\left(\right.g\left.\right)+H_{2}S\left(\right.g\left.\right)$ , if $K_{P}=64atm^{2}$ , equilibrium pressure of mixture is

• A. 8 atm
• B. 16 atm
• C. 64 atm
• D. 4 atm

Answer 1

Answer: (B)

$P_{N H_{3}}=P_{H_{2} S}$
So $K_{P}=\left(\right.P_{N H_{3}}\left(\left.\right)^{2}$
$64=\left(\right.P_{N H_{3}}\left(\left.\right)^{2}$
$P_{N H_{3}}=8$ atm
Total pressure $=P_{N H_{3}}+P_{H_{2} S}$
$=8+8=16$ atm