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  4. For NH 4 HS ( s ) leftharpoons NH 3( g )+ H 2 S ( g ), If Kp=64 atm 2 equilibrium pressure of mixture is

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Q. For $NH _{4} HS ( s ) \rightleftharpoons NH _{3}( g )+ H _{2} S ( g ),$ If $K_{p}=64\, atm ^{2}$ equilibrium pressure of mixture is

Equilibrium

Solution:

image

Total moles of gaseous substances $=2 x$

$x_{ H _{2} S }=x_{ NH _{3}}=\frac{1}{2} ;$

$p_{ H _{2} S }=p_{ NH _{3}}=\frac{P}{2}$

$K_{p}=p_{ H _{2} S } p_{ NH _{3}}=\frac{P^{2}}{4}$ or $64=\frac{P^{2}}{4}$

or, $P^{2}=64 \times 4=256$

$\therefore P=16$ atm .