1. Tardigrade
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  3. Chemistry
  4. For ion O2-, the bond order is

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Q. For ion $O_{2}^{-},$ the bond order is

J & K CETJ & K CET 2015Chemical Bonding and Molecular Structure

Solution:

Number of electrons in $O_{2}^{-}=8+8+1=17$
MO configuration of
$O_{2}^{-}=\sigma 1 s^{2}, \sigma^{*} 1 s^{2}, \sigma 2 s^{2}, \sigma^{*} 2 s^{2}, \sigma 2 p_{z}^{2}, \pi 2 p_{x}^{2}$
$\approx \pi 2 p_{y}^{2}, \pi^{*} 2 p_{x}^{2} \approx \pi^{*} 2 p_{y}^{1}$
Here, $N _{ b }$ (bonding electrons) $=10 N_{a}$ (antibonding electrons)
$=7 \because$ Bond order $=\frac{N_{b}-N_{a}}{2}$
$\therefore $ Bond order $=\frac{10-7}{2}=1.5$