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  4. For how long 2.5 ampere of current is passed to supply 54000 C of charge ?

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Q. For how long 2.5 ampere of current is passed to supply 54000 C of charge ?

Electrochemistry

Solution:

$Q = It$
$t = \frac{Q}{I} $
$ = \frac{54000}{2.5\,amp}$
$= 21600\,sec$
$ = \frac{21600}{60\times 60}$ hours
$= 6$ hours