Question

For $H^{+}$ the value of $\lambda^{\infty} =349.8\, S \,cm^2$ $eq^{-1}$. Calculate the mobilities of $H^{+}$ ion and its velocity if it is in a cell in which the electrodes are $5$ cm apart and to which a potential of $2$ volts is applied.

• A. $3.575 \times 10^{-3} cm^{2} volt^{-1} sec^{-1}, 1.43 \times 10^{-3} cm\, sec^{-1}$
• B. $5.2 \times 10^{-4} cm^{2} volt^{-1} sec^{-1}, 2.08 \times 10^{-4} cm\, sec^{-1}$
• C. $3.2 \times 10^{-4} cm^{2} volt^{-1} sec^{1}, 1.05 \times 10^{-3} cm\, sec^{-1}$
• D. $1.43 \times 10{-3} cm^{2} volt^{-1} sec^{-1}, 3.575 \times 10^{-3} cm\, sec^{-1}$

Answer 1

Answer: (A)

Velocity $=\frac{1}{2\times349.8}=1.48 \times10^{-3} cm/ sec $
Mobility $=1.43 \times10^{-3}\times\frac{5}{2}=3.575\times10^{-3}$