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Q. For given energy, $E=3.03 \times 10^{-19}$ joules corresponding wavelength is $\left(h=6.626 \times 10^{-34} J sec , c=3 \times 10^{8} m / sec \right)$

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Solution:

$E=\frac{h c}{\lambda}\Rightarrow \lambda$

$ =\frac{6 \cdot 626 \times 10^{-34} \times 3 \times 10^{8}}{3 \cdot 03 \times 10^{-19}}$

$=6.56 \times 10^{-7} m =656 \,nm$