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Q. For circuit the equivalent capacitance between P and Q isPhysics Question Image

BVP MedicalBVP Medical 2012

Solution:

$ \frac{1}{{{C}_{eq}}}=\frac{1}{3C}+\frac{1}{2C}+\frac{1}{C}=\frac{2+3+6}{6C}=\frac{11}{6C} $ $ {{C}_{eq}}=\frac{6C}{11} $

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