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Q. For bromine the IE/EA ratio $=10 / 3$, Electronegativity of bromine is 2.8 on Mulliken's scale, its EA in $kJ / mol$ will be ____.

Classification of Elements and Periodicity in Properties

Solution:

$IE =10 x ; EA =3 x$

According to Mulliken's scale

$X_{M}=\frac{I E+E A}{544} $

$2.8=\frac{10 x+3 x}{544}$

$\therefore x =\frac{2.8 \times 544}{13}=117 \,kJ$

$EA =3 x =117 \times 3=351$