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Q. For any two possible events $A$ and $B$ the expression $P\left(\frac{A}{A \cup B}\right)$ is always equal to

Probability - Part 2

Solution:

$\frac{P(A \cap(A \cup B))}{P(A \cup B)}=\frac{P(A)}{P(A \cup B)}=\frac{P(A \cup B)-P(B)+P(A \cap B)}{P(A \cup B)}$.