Question

For an object projected from ground with speed $u$ horizontal range is two times the maximum height attained by it. The horizontal range of object is

• A. $\frac{2 u^{2}}{3 g}$
• B. $\frac{3 u^{2}}{4 g}$
• C. $\frac{3 u^{2}}{2 g}$
• D. $\frac{4 u^{2}}{5 g}$

Answer 1

Answer: (D)

$R=24$ also, $\frac{H}{R}=\frac{1}{4} \tan \theta$
$\frac{H}{R}=\frac{1}{2}$
$\Rightarrow \frac{1}{2}=\frac{1}{4} \tan \theta$
$\tan \theta=2=\frac{P}{B}$
$R=\frac{2 u^{2} \sin \theta \cos \theta}{g}$
$R=\frac{2 u^{2}}{g}\frac{2}{\sqrt{5}} \times \frac{1}{\sqrt{5}}$
$R=\frac{4 u^{2}}{5 g}$