Question

For an isobaric process, the ratio of $\Delta Q$ (amount of heat supplied) to the $\Delta W$ (work done by the gas) is $\left(\gamma=\frac{C_{P}}{C_{V}}\right)$

• A. $\gamma$
• B. $\gamma-1$
• C. $\frac{\gamma}{\gamma+1}$
• D. $\frac{\gamma}{\gamma-1}$

Answer 1

Answer: (D)

For isobaric process $\Delta Q=n C_{p} \Delta T$ and $\Delta W=n R \Delta T$
So, $\frac{\Delta Q}{\Delta W}=\frac{C_{P}}{R}=\frac{C_{P}}{C_{P}-C_{V}}=\frac{1}{1-\frac{C_{V}}{C_{P}}}=\frac{\gamma}{\gamma-1}$
$\left[\because \frac{c_{P}}{c_{v}}=\gamma\right]$