Question

For an elementary chemical reaction, $A_2 \xrightleftharpoons[k_{-1}] {k_1}2A $ , the expression for $\frac{d[A]}{dt}$ is :

• A. $2k_1[A_2] - k_{-1} [A]^{2}$
• B. $k_1[A_2] - k_{-1} [A]^{2}$
• C. $2k_1[A_2] - 2k_{-1} [A]^{2}$
• D. $k_1[A_2] + k_{-1} [A]^{2}$

Answer 1

Answer: (C)

$A_2 \xrightleftharpoons[K_{-1}]{K_1} 2A $
$\frac{d\left[A\right]}{dt} =2k_{1} \left[A_{2}\right]- 2k_{-1}\left[A\right]^{2} $