1. Tardigrade
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  3. Chemistry
  4. For an electron, with n=3 has only one radial node. If the orbital angular momentum of the electron is given as √ X (h/2 π), then value of X will be

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Q. For an electron, with $n=3$ has only one radial node. If the orbital angular momentum of the electron is given as $\sqrt{ X } \frac{h}{2 \pi}$, then value of $X$ will be

Structure of Atom

Solution:

Number of radial nodes $=n-l-1=1$
$=3-l-1=1$
$\therefore l=1$
Orbital angular momentum $=\sqrt{(l+1)} \frac{h}{2 \pi}=\sqrt{2} \frac{h}{2 \pi}$