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  4. For a transistor, the current ratio αdc=(69/70). The current gain βdc is

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Q. For a transistor, the current ratio $\alpha_{dc}=\frac{69}{70}$. The current gain $β_{dc}$ is

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Solution:

As $\beta_{ DC }=\frac{\alpha_{ DC }}{1-\alpha_{ DC }} \Rightarrow \beta_{ DC }=\frac{69 / 70}{1-\frac{69}{70}}=\frac{69}{70-69}=69$