Question

For a transistor, the current amplification factor $\alpha $ is $0.8$ . If it is connected in common emitter configuration, the change in collector current when the base current changes by $6 \, mA$ is

• A. $6 \, mA$
• B. $4.8mA$
• C. $24 \, mA$
• D. $8 \, mA$

Answer 1

Answer: (C)

$I_{c}=\left(\frac{\alpha }{1 - \alpha }\right)I_{b}=\frac{0.8}{0.2}I_{b}=4I_{b}$
$I_{c}=$ collector current
$I_{b}=$ base current
$I_{c}=24mA$