Q. For a simple pendulum, the graph between $ {{T}^{2}} $ and $ L $ is
Solution:
$ T=2\pi \sqrt{\frac{L}{g}} $
Or $ T\propto \sqrt{L} $
or $ {{T}^{2}}\propto L $
It is linear relation between $ {{T}^{2}} $ and $ l $ hence the graph between $ {{T}^{2}} $ and L is a straight line passing through the origin.
