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  4. For a screw gauge least count of the main scale is 1 mm. Find the minimum number of divisions on the circular scale so that it can measure a diameter of 5 μm

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Q. For a screw gauge least count of the main scale is $1 \, mm.$ Find the minimum number of divisions on the circular scale so that it can measure a diameter of $5 \, μm$

NTA AbhyasNTA Abhyas 2020

Solution:

Least count of screw gauge $=5 \, μm$
$L.C=\frac{pitch}{no . \, of \, div \, on \, circular \, scale}$
$5μm=\frac{1 mm}{N}$
$N=200$