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Q. For a reversible thermodynamic process for monoatomic gas $PV^{x}=$ constant. If for this process $x=\frac{C_{P}}{C_{V}},$ then heat capacity for the process is :-

NTA AbhyasNTA Abhyas 2022

Solution:

$x=\frac{C_{P}}{C_{V}}=\gamma $ so, process is an adiabatic process.
So, heat capacity $=0$