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  4. For a reaction X arrow Y, the graph of the product concentration (x) versus time (t) came out to be a straight line passing through the origin. Hence the graph of (-d[X]/dt) and time would be

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Q. For a reaction $X \rightarrow Y$, the graph of the product concentration $(x)$ versus time $(t)$ came out to be a straight line passing through the origin. Hence the graph of $\frac{-d\left[X\right]}{dt}$ and time would be

AIIMSAIIMS 2010Chemical Kinetics

Solution:

If product concentration is x.

For a zero order reaction $\frac{x}{t}=k$


Thus graph would be a straight line passing through origin. So the given information is for zero order reaction. For a zero order reaction, rate of the reaction is constant. Thus, plot of rate vs time, i.e., $-\frac{d\left[X\right]}{dt}$ vs time will be a straight line parallel to x-axis.