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  4. For a reaction, given below is the graph of ln k vs (1/ T ). The activation energy for the reaction is equal to cal mol -1. (Nearest integer). (Given: R =2 cal K -1 mol -1 )

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Q. For a reaction, given below is the graph of $\ln k$ vs $\frac{1}{ T }$. The activation energy for the reaction is equal to ___ cal $mol ^{-1}$. (Nearest integer).
(Given : $R =2 \,cal\, K ^{-1} \,mol ^{-1}$ )Chemistry Question Image

JEE MainJEE Main 2022Chemical Kinetics

Solution:

$ K = Ae ^{- Ea / RT } $
$ \ln k =\frac{- Ea }{ RT }+\ln A $
$ \text { Slope }=\frac{ Ea }{ R }=\frac{20}{5} $
$E _{ a }=4 R =8\, Cal / mol $