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Q. For a radioactive element, $\tau=$ ______$\tau_{1 / 2}$

Gujarat CETGujarat CET 2019

Solution:

$\tau_{\text {mean }} \times \ln 2=\tau_{1 / 2}$
$\tau_{\text {mean }}=\tau_{1 / 2}(1 / \ln 2)$
$=1.44 \tau_{1 / 2}$