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Q. For a party $8$ guests are invited by a husband and his wife. They sit in a row for dinner. The probability that the husband and his wife sit together is

Bihar CECEBihar CECE 2007

Solution:

Total number of way of sitting $=9 !$
and number of favourable ways of sitting $=2 \times 8 !$
$\therefore $ Required probability $=\frac{2 \times 8 !}{9 !}=\frac{2}{9}$.