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  4. For a particle executing simple harmonic motion, the kinetic energy K is given by, K=K0 cos 2ω t. The maximum value of potential energy is

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Q. For a particle executing simple harmonic motion, the kinetic energy $K$ is given by, $ K={{K}_{0}}{{\cos }^{2}}\omega t. $ The maximum value of potential energy is

BHUBHU 2008

Solution:

$K_{\max }=K_{0}=$ total energy
As total energy remains conserved in SHM, hence when $U$ is maximum in $SHM , K=0$,
ie, $E$ is also equal to
$U_{\max }$, ie, $U_{\max }=E=K_{0}$.