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Q. For a normal eye, the distance between the retina and the cornea eye lens is $2.5\, cm$. If least converging power of eye lens is $30\,D$, then find converging power of cornea of eye.

Ray Optics and Optical Instruments

Solution:

$P =\frac{100}{ v }-\frac{100}{ u }$
$P =\frac{100}{2.5}-\frac{100}{-\infty}$
$P =40\, D$
$P = P _{1}+ P _{2}$
$40=30+ P _{2}$
$P _{2}=10 \,D$