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  4. For a given surface the Gauss's law is stated as oint vecE ⋅ d vecA=0. From this we can conclude that

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Q. For a given surface the Gauss's law is stated as $\oint \vec{E} \cdot d \vec{A}=0$. From this we can conclude that

Electric Charges and Fields

Solution:

$\oint \vec{E} \cdot d \vec{A}=0$, represents charge inside close surface is zero. Electric field as any point on the surface may be zero.