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Q. For a gas if ratio of specific heats at constant pressure and volume is $\gamma$ then value of degrees of freedom is

BITSATBITSAT 2012

Solution:

$\gamma =1 +\frac{2}{f}$,
$ \Rightarrow \gamma -1 =\frac{2}{f} $
$ \Rightarrow f =\frac{2}{\gamma -1}$