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Q. For a gas having molar mass $M,$ specific heat at constant pressure per gram of gas is given by

Thermodynamics

Solution:

$C_{p}-C_{v}=R$ and $\frac{C_{p}}{C_{v}}=\gamma$

$\therefore C_{p}-\frac{C_{p}}{\gamma}=R$ or $C_{p}\left(\frac{\gamma-1}{\gamma}\right)=R$

or $C_{p}=\frac{R \gamma}{(\gamma-1)}=M \bar{C}_{p}$ or $\bar{C}_{p}=\frac{\gamma R}{M(\gamma-1)}$