Tardigrade
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Tardigrade
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Chemistry
For a first order reactions,
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Q. For a first order reactions,
Chemical Kinetics
A
$t_{1 / 2}=\frac{k}{a}$
B
$t_{3 / 4}=2 t_{1 / 2}$
C
$t_{1 / 2}=\frac{0.693}{k}$
D
$t_{1 / 2}=k \times 0.693$
Solution:
Correct answer is (b) $t_{3 / 4}=2 t_{1 / 2}$Correct answer is (c) $t_{1 / 2}=\frac{0.693}{k}$