Question

For a decomposition of azoisopropane at $270^\circ C$ it was found that at t = 0, the total pressure was 33.15 mm of Hg and after 3 minutes the total pressure was found to be 46.3 mm of Hg. Calculate the value of K for this reaction.

$\left( CH _{3}\right)_{2} CHN = NCH \left( CH _{2}\right)_{2} \rightarrow N _{2}+ C _{6} H _{14}$

• A. 0.168 $min^{- 1}$
• B. 0.173 $min^{- 1}$
• C. 0.18 $min^{- 1}$
• D. $0.154$ $min^{- 1}$

Answer 1

Answer: (A)

$k=\frac{2.303}{t}log\frac{p_{o} \left(\right. n - 1 \left.\right)}{n p_{o} - p_{1}}$

$k=\frac{2.303}{3}log\frac{33.15 \left(\right. 2 - 1 \left.\right)}{2 \times 33.15 - 46.3}$

$k=0.168$ $min^{- 1}$