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Q. For a concave mirror, if virtual image is formed, the graph between $m$ and $u$ is of the form

Ray Optics and Optical Instruments

Solution:

In concave mirror, if virtual images are formed, $u$ can have values zero and $f$
At $u=0, m=\frac{f}{f-u}=\frac{f}{f}=1$
At $u=f, m=\frac{f}{f-u}=-\frac{f}{-f-(-f)}=\infty$