Question

For a chemical reaction, $A \to B$, it is found that the rate of reaction doubles when the concentration of $A$ is increased four times. The order in terms of $A$ for this reaction is

• A. two
• B. one
• C. half
• D. zero

Answer 1

Answer: (C)

rate $\left(r_{1}\right)=k[A]^{n}$ (where, $n$ is order of reaction) $\dots (i)$

$2 r_{1}=k[4 A]^{n}$ $\dots(ii)$

On solving equation (i) and (ii), $n=\frac{1}{2}$