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Q. For a certain redox reaction, $E ^{0}$ is positive. This means that:

Electrochemistry

Solution:

$\Delta G ^{0}=- nFE ^{0}.......(i)$

$\Delta G^{0}=-2.303 RT \log K _{ eq}.....(ii)$

From eq (i) if $E ^{0}$ is positive

then $\Delta G ^{0}$ is negative In equation (ii), $\Delta G^{0}$ is negative

So; $\log K >0 \Rightarrow K >1$