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  3. Chemistry
  4. For a Cannizzaro reaction, R-CHO + NaOH→ Rate law is derived as: Rate=k[RCHO]2[HO-]2 From the above rate law, it can be concluded that

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Q. For a Cannizzaro reaction,
$R-CHO + NaOH\to$ Rate law is derived as: Rate$=k\left[RCHO\right]^{2}\left[HO^{-}\right]^{2}$ From the above rate law, it can be concluded that

Aldehydes Ketones and Carboxylic Acids

Solution:

For formation of dianion hydride donor, an additional mole of $NaOH$ is consumed
image
Hence, rate becomes $2^{nd}$ order with respect to $HO^{-}$ and fourth order overall.